Based on their specific weights at 20*C
1 litre of Acetone would weigh 784.58g
1 litre of Methanol would weigh 787.73g
Additional weight for Methanol is 3.15g per litre.
So if for example 1 litre condensed distillate recovered after processing weighs say 785.30g
This would mean an additional 0.72g over the expected weight of just Acetone.
So by working out the percentage of the additional amount we can work out the volume of methanol.
eg. 0.72 divided by 3.15 = 0.2286
To get a percentage we times by 100
0.2286x100 = 22.86% and since we used 1 litre as a starting point
22.86% of 1 litre is 228.6 ml of Methanol
So we can then use this in the next batch, knowing how much Meth and how much Acetone we have in the distillate we can work out the volumes required.
I think this is right but please correct me if I am wrong I am not a chemist or mathematician!
