As per the end of this thread -
http://www.biopowered.co.uk/forum/index.php/topic,762.0/topicseen.html...ive been wondering about the amount of methaol used on s1 of the 2stage 'no titration' method.
My feedstock is very variable, and ive had a couple of reactions recently that have not achieved very high conversion on the first stage. Im pretty sure this was due to high titration, as one of the batches i was especially carefull with drying.
Anyhow, i have always considered s1 of the 2stage to be the 'leveler' - to remove all the unknowns and get to a point where s2 can be run without unexpected outcome.
Tony comments in the thread linked to about the glyc possibly taking out the bulk of the meth, which comes back to what ive been thinking about the quantity of meth used on s1.
For example -
If S1 is run with 80% for the batch, but the feedstock titrates unusually highly, then there will be limited catalyst and excess meth. If the glyc at the end of s1 takes out the bulk of the meth, then s2 (if only the remaining 20% is used) would work out limited by the methanol.
I have been thinking that possibly a much much more limited s1 may be advantageous, with regard to methanol consumption.
With my next batch, i think i may do somthing like -
200ltrs of feedstock
aim to react, say, 50 ltrs on s1, so add
15% of 50ltrs of methanol (7.5ltrs)
5g of naoh for 50 ltrs (250g) (or possibly more?)
on s2 i would probably use 15% methanol for the unconverted, and a further 5g / ltr of naoh.When i initially started using the 2stage no titration method, i aimed to get as high a conversion possible on s1, so as to reduce the error (and possible soap formation) on s2. But since then, ive realised that soap formation does not seem to be my main enemy - i would rather focus my attention on reducing the methanol used.